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Multiple Choice
A student prepared a stock solution by dissolving 20.0 g of KOH in enough water to make 150.0 mL of solution. She then took 15.0 mL of the stock solution and diluted it with enough water to make a final solution of 65.0 mL. What is the concentration of the final solution in mol/L?
A
0.153 M
B
0.230 M
C
0.615 M
D
0.307 M
Verified step by step guidance
1
Calculate the molar mass of KOH by adding the atomic masses of potassium (K), oxygen (O), and hydrogen (H).
Determine the number of moles of KOH in the stock solution by dividing the mass of KOH (20.0 g) by its molar mass.
Calculate the concentration of the stock solution in mol/L by dividing the number of moles of KOH by the volume of the stock solution in liters (150.0 mL converted to liters).
Use the dilution formula \( C_1V_1 = C_2V_2 \) to find the concentration of the final solution, where \( C_1 \) is the concentration of the stock solution, \( V_1 \) is the volume of the stock solution used (15.0 mL), \( C_2 \) is the concentration of the final solution, and \( V_2 \) is the final volume (65.0 mL).
Solve for \( C_2 \) to find the concentration of the final solution in mol/L.