Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

17. Acid and Base Equilibrium

pH of Strong Acids and Bases

General Chemistry

17. Acid and Base Equilibrium

pH of Strong Acids and Bases

Previous problemNext problem

Struggling with General Chemistry?

Join thousands of students who trust us to help them ace their exams!Watch the first video

Multiple Choice

Determine the pH of a 7.8×10⁻⁴ M Ba(OH)₂ solution.

11.89

12.09

1.91

2.11

Previous problemNext problem

Verified step by step guidance

Start by understanding that Ba(OH)₂ is a strong base, which dissociates completely in water. Each formula unit of Ba(OH)₂ produces two hydroxide ions (OH⁻).

Calculate the concentration of hydroxide ions (OH⁻) in the solution. Since Ba(OH)₂ dissociates into one Ba²⁺ ion and two OH⁻ ions, the concentration of OH⁻ ions will be twice the concentration of Ba(OH)₂. Use the formula: [OH⁻] = 2 × [Ba(OH)₂].

Substitute the given concentration of Ba(OH)₂ into the formula: [OH⁻] = 2 × 7.8×10⁻⁴ M. This will give you the concentration of OH⁻ ions in the solution.

Next, calculate the pOH of the solution using the formula: pOH = -log₁₀[OH⁻]. Substitute the concentration of OH⁻ ions you calculated into this formula to find the pOH.

Finally, determine the pH of the solution using the relationship between pH and pOH: pH = 14 - pOH. Substitute the pOH value you calculated to find the pH of the solution.