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Multiple Choice
A 5.65 g sample of a weak acid with Ka=1.3×10⁻⁴ was combined with 5.20 mL of 5.90 M NaOH and the resulting solution was diluted to 750 mL. The measured pH of the solution was 4.20. What is the molar mass of the weak acid?
A
210.4 g/mol
B
120.1 g/mol
C
180.3 g/mol
D
150.2 g/mol
Verified step by step guidance
1
First, identify the chemical reaction taking place. The weak acid reacts with NaOH to form its conjugate base and water. Write the balanced chemical equation for this reaction.
Calculate the moles of NaOH used in the reaction. Use the formula: \( \text{moles of NaOH} = \text{volume (L)} \times \text{molarity (M)} \). Convert the volume from mL to L before calculation.
Determine the moles of the weak acid that reacted with NaOH. Since NaOH is a strong base, it will react completely with the weak acid. The moles of NaOH will be equal to the moles of the weak acid that reacted.
Calculate the concentration of the conjugate base formed after the reaction. Use the formula: \( \text{concentration} = \frac{\text{moles of conjugate base}}{\text{total volume of solution (L)}} \). The total volume is 750 mL, converted to liters.
Use the Henderson-Hasselbalch equation to relate the pH, pKa, and the ratio of the concentrations of the conjugate base and the weak acid. Rearrange the equation to solve for the initial concentration of the weak acid, and then use this to find its molar mass by dividing the mass of the sample by the moles of the weak acid.