Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
How many grams of alum (KAl(SO4)2·12H2O) can be produced from 20.0 g of aluminum (Al) when the reaction proceeds with 100% yield?
A
23.7 g
B
47.3 g
C
94.6 g
D
189.2 g
Verified step by step guidance
1
Start by writing the balanced chemical equation for the reaction. The reaction involves aluminum reacting with potassium sulfate and sulfuric acid to form alum (KAl(SO4)2·12H2O). The balanced equation is: 2 Al + 2 K2SO4 + 6 H2SO4 + 24 H2O → 2 KAl(SO4)2·12H2O.
Calculate the molar mass of aluminum (Al). The atomic mass of aluminum is approximately 26.98 g/mol.
Determine the number of moles of aluminum you have. Use the formula: \( \text{moles of Al} = \frac{\text{mass of Al}}{\text{molar mass of Al}} \). Substitute the given mass of aluminum (20.0 g) and its molar mass to find the moles.
Using the stoichiometry from the balanced equation, find the moles of alum (KAl(SO4)2·12H2O) that can be produced. According to the equation, 2 moles of Al produce 2 moles of alum, so the moles of alum will be equal to the moles of Al.
Calculate the mass of alum produced using its molar mass. First, find the molar mass of KAl(SO4)2·12H2O by adding the atomic masses of all atoms in the formula. Then use the formula: \( \text{mass of alum} = \text{moles of alum} \times \text{molar mass of alum} \) to find the mass.