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Multiple Choice
Given that the enthalpy change (ΔH) for the formation of H2O(g) from its elements is -926.29 kJ/mol, what is the approximate bond energy of the O-H bond in water?
A
463 kJ/mol
B
1852 kJ/mol
C
231 kJ/mol
D
926 kJ/mol
Verified step by step guidance
1
Understand that the enthalpy change (ΔH) for the formation of water vapor (H2O(g)) from its elements involves breaking and forming bonds. The reaction can be represented as: H2(g) + 1/2 O2(g) → H2O(g).
Recognize that the enthalpy change given (-926.29 kJ/mol) is for the formation of one mole of water vapor from its elements in their standard states.
Recall that the bond energy is the energy required to break one mole of a bond in a gaseous substance. For water, the O-H bond energy is the energy needed to break the O-H bonds in H2O(g).
Since water has two O-H bonds, the total energy required to break both O-H bonds in one mole of water is twice the bond energy of a single O-H bond.
To find the bond energy of a single O-H bond, divide the total enthalpy change for the formation of water by 2, as there are two O-H bonds in each water molecule.