Enter the K sp expression for C 2 D 3 in terms of the molar solubility x.

Hey everyone, we're asked for the correct KsB expression, which is our solid ability product constant for cadmium arsenic first, let's go ahead and write out our reaction. So we have cadmium arsenic and we know that this is in its solid state. Now this will dissociate into our cadmium ions, plus our Arsene ions. Now, in order to balance out this reaction, we need to add a coefficient of three prior to our cadmium and a coefficient of two prior to our Arson eight. Now, solving for our K. S. P, we know this is going to be our products over our reactant. So in this case we have our cadmium ion which will be raised to the power of three since we have that coefficient of three and we're going to multiply this by our Arsene ion Which will be raised to the power of two due to that coefficient of two. And since solids are ignored in our KsB expression, our final answer here is going to be answer choice. A now, I hope this made sense. And let us know if you have any questions