In Exercises 27 - 36, find (if possible) the following matrices: ...

Question

In Exercises 27 - 36, find (if possible) the following matrices: a. ABb. BA12A = [1 2 3 4], B = 34

Accepted Answer

find the given matrix seats. If possible we have two major seats P. Q. And Q. P. Now multiply these agencies if the number of rows and our first matrix equals the number of columns of our second matrix. So we have one row and P1 column in Q. We can multiply those together. What's the gap PQ. Now we're gonna multiply the first part of our matrix p times the first part of our matrix. Q. So our first part we have native five times 85. Then we have plus our next part two and two. Then one times 1 and one times 1. Since there's only one road run column this will be a one by one matrix. You will get 25 plus four plus one plus one. This gives us 31. Now I want to go ahead and solve for Q. P. Q. P. We're gonna look at the number of rows and Q and the number of columns Mp. We have four rows and Q four columns and p. We're gonna end up with a four by four matrix. Now because we have four rows four columns so Q. Look at the number In our first part of Q. We have negative five, Multiplied by -5. That is our first one. Then we have negative five times 2 -5 times 1 -5 times one. Then we go down to two. Our next part is to from Q 2000 to 5 two times 22 times 12 times one. Now we have one negative 51 times 21 times 11 times one. Finally one day the 512111 and one. We can simplify this. Now you have -5 times negative 5 25 85 times. to negative 10 five and negative five. Next drop Native 10 42 and two 85211 and -5211. We can't simplify this any further. So R p q 31 Q p. Is this matrix this four by four. We look at our answers. The answer to our problem is answer A. Okay. I hope help you solve the problem. Thank you for watching. Goodbye.

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In Exercises 27 - 36, find (if possible) the following matrices: a. ABb. BA12A = [1 2 3 4], B = 34

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