In Exercises 33–38, express the function, f, in simplified form. ...

Question

In Exercises 33–38, express the function, f, in simplified form. Assume that x can be any real number._______f(x) = ³√48(x-2)³

Accepted Answer

Completely simplify the following function note that any variable that appears represents positive numbers where our function F and V is equals to the cube group Of 1 35 multiplied by V -17 to the 3rd. Now with the cube group, we can simplify anything that has a perfect cube. We notice here we have a V -17 to the third. We'll be able to simplify that directly with our radical. However, we can't simplify the 1:35 directly because 1:35 is not a perfect. However, we can find factors of 1:35 to rewrite this 1 35 possible factors include and five. We can then direct this as 27 multiplied by five, Multiplied by V -17 to the 3rd. Now we have this, we can rewrite our radical. Since everything under the radical has the same root, you will say the Q root of 27 multiplies the cube root of five, which multiplies the Q group of V minus 17 to the third. Now we know the tubular 27 is three Cubit of five does not simplify. So we will leave that as the cubit of five. And finally, the Cube root of V -17 to the third simplifies such as V -17. We can't simplify this any further. So I answer three multiplied by the cubit of five multiplied by V -17 corresponds to answer D OK. I hope to help you solve the problem. Thank you for watching. Goodbye.

Struggling with College Algebra?

In Exercises 33–38, express the function, f, in simplified form. Assume that x can be any real number._______f(x) = ³√48(x-2)³

Watch next

Radical Expressions practice set