Solve each equation in Exercises 15–34 by the square root property.(2x + 8)^2 = 27

Solve each equation in Exercises 15–34 by the square root property.(x + 3)^2 = - 16

Solve each equation using the square root property. See Example 2. x^2 = 121

Solve each equation using the square root property. See Example 2. x^2 = -400

Solve each equation using the square root property. See Example 2. (x - 4)^2 = -5

In Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial.x^2 + 12x

Solve each equation. -2x² +11x = -21

Solve each equation. (2x+1)(x-4) = x

(Modeling)Solve each problem. See Example 3.Height of a ProjectileA projectile is launched from ground level with an initial velocity of v_0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by s=-16t^2+v_0t. In each exercise, find the time(s) that the projectile will (a) reach a height of 80 ft and (b) return to the ground for the given value of v_0. Round answers to the nearest hun-dredth if necessary. v_0=96