Graph each equation in Exercises 13 - 28. Let x = - 3, - 2, - 1, ...

Question

Graph each equation in Exercises 13 - 28. Let x = - 3, - 2, - 1, 0, 1, 2, 3y = |x| + 1

Accepted Answer

graph the following equation. Using this set of X values from negative 3 to 3. And we have our equation why equals five x plus 1 -4. What I'm first gonna do is I'm gonna make a table of values. So let's say we have X and y. 1st 1 is -3, negative two, negative one and so on until we get to three. Now for a why do you want to do is plug in Everyone of her ex values skin output into our equation. What? So for instance we have Y equals absolute value. Our first one is negative three. So we'd say negative three plus one minus four. That would be equal To the absolute value of - minus four Which would give us 2 -4. This is just negative two. So our first point is at 3 -2. Now we do the same for every number after this. So negative two for instance. Well we plugged in negative two. Here we get negative two plus one, negative one, absolute value of that one plus four is negative three. And we do the same for the rest of these points. So -1 B negative for zero B -3 one negative two. To be negative one three would be zero. Now we have our list of points, we can determine what our graph looks like. They want to find a graph that has negative three negative two negative two, negative three. And so on. Pretty much all of our points. So let's look at our graphs and try to find -3, 1st. Well this one for a negative three goes all the way down to negative six. So we can't say it's a what about B if negative three, that goes up to positive six, we can't say it's be either. In that case let's look at sea. We have negative three on the X. Going down negative two on the way. Let's go ahead and check the rest of our points just to be sure we have negative two negative three. So negative two over down to negative three. That is correct. You have negative one, Next 10 0, negative three one negative two, two and 8 of one and 30. Those points correspond with this graph, so the answer to our problem is answer C. Okay. I hope to help you solve the problem. Thank you for watching. Goodbye.

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Graph each equation in Exercises 13 - 28. Let x = - 3, - 2, - 1, 0, 1, 2, 3y = |x| + 1

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