Find each product. Write answers in standard form. i(3-4i)(3+4i)

Question

Accepted Answer

Hello everyone. We're going to perform multiplication on the expression I times seven minus 13 I times seven plus 13. I I recall that if I have binomial that have the same terms but opposite signs in the middle. This results in the difference of squares. So I'm going to take care of that part first. I'm gonna leave the eye on the outside of my parentheses. And I'm going to recall that when I have the difference of squares, I square the first term. So seven squared is 49. I squared the last term. So 13 squared is 169 and then I squared is I squared. They put a minus in between them. So before I move on to multiplying I in from the outside I want to take care of the I squared Recall that I squared is the same as negative one So I can replace it with -1. And I have i times in parentheses 49 -169 times negative. I So I'm gonna do 169 times negative. I So again I still on the outside of the parentheses 49 and then -169 times a negative one. It's like plus 169. Since those are both real numbers before I multiply the eye and I'm gonna add them together. So 49 plus 169 results in 218 And now I can multiply the I in 218 times I Is 218. I this would be considered in standard form because there is no real part. It is just an imaginary number. And so our answer choice is answer choice a have a good day.

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Find each product. Write answers in standard form. i(3-4i)(3+4i)

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