use-a-shift-to-explain-how-the-graph-of-hxx26x27hxsqrt-x2-6x27-is-obtained-from-

Question

Use a shift to explain how the graph of $h(x)=\sqrt{-x^2-6x+27}$ is obtained from the graph of $p(x)=\sqrt{36-x^2}$ . Which of the following transformations applies? Draw the graph of h(x).

Accepted Answer

Shift the graph of p(x) to the left side by 3 units. Graph comparing h(x) and p(x) for calculus transformations topic.

Answer

Shift the graph of p(x) to the right side by 3 units. Graph comparing p(x) and h(x) for calculus transformations topic.

Answer

Stretch the graph of p(x) vertically by a factor of 3. Graph comparing h(x) and p(x) for calculus transformations topic.

Answer

Shift the graph of p(x) to the left side by 3 units. Graph comparing p(x) and h(x) for calculus transformations topic.

Use a shift to explain how the graph of h(x)=−x2−6x+27h(x)=\sqrt{-x^2-6x+27}h(x)=−x2−6x+27 is obtained from the graph of p(x)=36−x2p(x)=\sqrt{36-x^2}p(x)=36−x2 . Which of the following transformations applies? Draw the graph of h(x).

Use a shift to explain how the graph of $h(x)=\sqrt{-x^2-6x+27}$ is obtained from the graph of $p(x)=\sqrt{36-x^2}$ . Which of the following transformations applies? Draw the graph of h(x).