find-the-equation-of-the-tangent-line-to-the-curve-hh-at-the-point-chcc-hc-where

Question

Find the equation of the tangent line to the curve $h$ at the point $(c, h (c))$ where $h of x equals 41 x squared$ and $c equals 1$ .

Accepted Answer

$y = 82 x - 41$

Answer

$y = 82 x - 41$

Answer

$y = 82 x - 41$

Answer

$y = 82 x - 41$

Find the equation of the tangent line to the curve hh at the point (c,h(c))(c, h(c)) where h(x)=41x2h\left(x\right)=41x^2 and c=1c=1.