Calculus
h′(x)=4x2ln(x)−1⋅ln(x)h^{\prime}\left(x\right)=4x^{2\ln\left(x\right)-1}\cdot\ln\left(x\right)
h′(e)=4eh^{\prime}\left(e\right)=4e^{}
h′(x)=4x2ln(x)⋅ln(x)h^{\prime}\left(x\right)=4x^{2\ln\left(x\right)}\cdot\ln\left(x\right)
h′(e)=4e2h^{\prime}\left(e\right)=4e^2
h′(x)=8x2ln(x)−1⋅ln(x)h^{\prime}\left(x\right)=8x^{2\ln\left(x\right)-1}\cdot\ln\left(x\right)
h′(e)=8eh^{\prime}\left(e\right)=8e^{}
h′(x)=8x2ln(x)⋅ln(x)h^{\prime}\left(x\right)=8x^{2\ln\left(x\right)}\cdot\ln\left(x\right)
h′(e)=8e2h^{\prime}\left(e\right)=8e^2