calculate-the-first-second-and-third-derivatives-of-the-function-kx2x64x59x3-kx-

Question

Calculate the first, second, and third derivatives of the function $k(x) = 2x^6 + 4x^5 + 9x^3$ .

Accepted Answer

$k^{'} (x) = 12 x^{5} + 20 x^{4} + 27 x^{2}$

$k^{'}$ $^{'} (x) = 60 x^{4} + 80 x^{3} + 54 x$

$k^{'}$ $'$ $^{\prime}\left(x\right)=$ $240 x^{3} + 240 x^{2} + 54$

Answer

$k^{'} (x) = 12 x^{5} + 20 x^{4} + 27 x^{2}$

$k^{'}$ $^{'} (x) = 60 x^{4} + 80 x^{3} + 54 x$

$k^{'}$ $'$ $^{'} (x) =$ $12 x^{3} + 20 x^{2} + 27$

Answer

$k^{'} (x) = 12 x^{5} + 20 x^{4} + 27 x^{2}$

$k^{'}$ $^{'} (x) = 60 x^{4} + 80 x^{3} + 54 x$

$k^{'}$ $'$ $^{\prime}\left(x\right)=$ $240 x^{3} + 240 x^{2} + 54$

Answer

$k^{'} (x) = 12 x^{5} + 20 x^{4} + 27 x^{2}$

$k^{'}$ $^{'} (x) = 60 x^{4} + 80 x^{3} + 54 x$

$k^{'}$ $'$ $^{\prime}\left(x\right)=$ $240 x^{3} + 240 x^{2} + 54$

Calculate the first, second, and third derivatives of the function k(x)=2x6+4x5+9x3 k(x) = 2x^6 + 4x^5 + 9x^3 k(x)=2x6+4x5+9x3.