Calculus
y=3cos(2x−π2)+2y=3\cos\left(2x-\frac{\pi}{2}\right)+2y=3cos(2x−2π)+2
y=3cos(2x−π2)−2y=3\cos\left(2x-\frac{\pi}{2}\right)-2y=3cos(2x−2π)−2
y=3cos(2x+π2)+2y=3\cos\left(2x+\frac{\pi}{2}\right)+2y=3cos(2x+2π)+2
y=3cos(2x+π2)−2y=3\cos\left(2x+\frac{\pi}{2}\right)-2y=3cos(2x+2π)−2