Find the absolute maximum and minimum values of the function $h$ on the interval $[-1, 3]$.
$h(x) = 5x^3 e^{-2x}$

$\text{Absolute maximum}=-\frac{135}{8}{e}^{-3}\text{ at }x=-1,\text{Absolute minimum}=5e^2\text{ at }x=\frac{3}{2}$

$\text{Absolute maximum}=-\frac{135}{8}{e}^{-3}\text{ at }x=\frac{3}{2},\text{Absolute minimum}=5e^2\text{ at }x=-1$

$\text{Absolute maximum}=\frac{135}{8}{e}^{-3}\text{ at }x=\frac{3}{2},\text{Absolute minimum}=-5e^2\text{ at }x=-1$

$\text{Absolute maximum}=\frac{135}{8}{e}^{-3}\text{ at }x=-1,\text{Absolute minimum}=-5e^2\text{ at }x=\frac{3}{2}$