find-the-critical-points-of-the-function-fxcos3x2fxcos3x-2-on-the-interval-22-fr

Question

Find the critical points of the function $f (x) = \cos (3 x) - 2$ on the interval $[- \frac{π}{2}, \frac{π}{2}]$ . Identify the absolute maximum and minimum values.

Accepted Answer

Critical points: $f (x) = \cos (3 x) - 2$

$f_{\max} (0) = - 1$

$f_{\min} (- \frac{π}{3}) = - 3$ and $f_{\min} (\frac{π}{3}) = - 3$

Answer

Critical points: $f (x) = \cos (3 x) - 2$

$f sub max of 0 equals 3$

$f_{\min} (- \frac{π}{3}) = 0$ and $f_{\min} (\frac{π}{3}) = 0$

Answer

Critical points: $f (x) = \cos (3 x) - 2$

$f_{\max}\left(0\right)=-1$

$f_{\min}\left(-\frac{\pi}{3}\right)=-3$

Answer

Critical points: $f (x) = \cos (3 x) - 2$

$f sub max of 0 equals 3$

$f_{\min}\left(-\frac{\pi}{3}\right)=-3$

Find the critical points of the function f(x)=cos(3x)−2f(x)=\cos(3x)-2 on the interval [−π2,π2][-\frac{\pi}{2},\frac{\pi}{2}]. Identify the absolute maximum and minimum values.

Find the critical points of the function $f (x) = \cos (3 x) - 2$ on the interval $[- \frac{π}{2}, \frac{π}{2}]$ . Identify the absolute maximum and minimum values.