Find the derivative of the function $f\left(x\right)=\frac{2\cos x+3\sin x}{2\cos x-3\sin x}$.

$f^{\prime }\left(x\right)=\frac{12}{2\cos x+3\sin x}$

$f^{\prime }\left(x\right)=\frac{12}{2\cos x-3\sin x}$

$f^{\prime }\left(x\right)=\frac{12}{{(2\cos x+3\sin x)}^2}$

$f^{\prime }\left(x\right)=\frac{12}{{(2\cos x-3\sin x)}^2}$