Find the extreme values of $f\left(x\right)=\frac{242}{5}{x}^5-\frac{3874}{3}{x}^3+32x$. Round to two decimal places if necessary.

Local minima: $-1.94$ at $x=-\frac{1}{11}$ and $-32955.73$ at $x=4$

Local maxima: $32955.73$ at $x=-4$ and $1.94$ at $x=\frac{1}{11}$

Local minima: $-1.94$ at $x=\frac{1}{11}$ and $-32955.73$ at $x=4$

Local maxima: $32955.73$ at $x=-4$ and $1.94$ at $x=-\frac{1}{11}$

Local minima: $-1.32$ at $x=-\frac{1}{22}$ and $-16288.73$ at $x=2$

Local maxima: $16288.73$ at $x=-2$ and $1.32$ at $x=\frac{1}{22}$

Local minima: $-1.32$ at $x=\frac{1}{22}$ and $-16288.73$ at $x=2$

Local maxima: $16288.73$ at $x=-2$ and $1.32$ at $x=-\frac{1}{22}$