Determine the derivative of $f\left(x\right)=\frac{2x^2-3x}{x}$ using the quotient rule.

$f^{\prime }\left(x\right)=$ $4$

$f^{\prime }\left(x\right)=$ $4$$x$

$f^{\prime }\left(x\right)=$ $2x$

$f^{\prime }\left(x\right)=$ $2$