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Finding Limits Algebraically
1. Limits and Continuity / Finding Limits Algebraically / Problem 6
Problem 6

Use the following theorem to evaluate limx0sin39x9x\displaystyle \lim_{x \to 0}{\frac{\sin{39x}}{9x}}:
limx0sinxx=1\displaystyle \lim_{x \to 0}{\frac{\sin{x}}{x}}=1

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