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Question

For the function $f (x)$ given by $f (x) = {\begin{matrix} 2 x + 4 c, if x \leq - 1 \\ x^{2} + 5 c - d, if - 1 < x \leq 2 \\ 4 x - 7, if x > 2 \end{matrix}$ , find the values of $c$ and $d$ that make it continuous everywhere.

Accepted Answer

$c equals 0$

$d equals 3$

Answer

$c equals 0$

$d equals 3$

Answer

$c equals 0$

$d=3$

Answer

$c=0$

$d = - 3$

For the function f(x)f(x) given by f(x)={2x+4c, if x≤−1x2+5c−d, if −1<x≤24x−7, if x>2f(x)=\begin{cases}2x+4c,\text{ if }x\leq-1\\ x^2+5c-d,\text{ if }-1<x\leq2\\ 4x-7,\text{ if }x>2\end{cases}, find the values of cc and dd that make it continuous everywhere.

For the function $f (x)$ given by $f (x) = {\begin{matrix} 2 x + 4 c, if x \leq - 1 \\ x^{2} + 5 c - d, if - 1 < x \leq 2 \\ 4 x - 7, if x > 2 \end{matrix}$ , find the values of $c$ and $d$ that make it continuous everywhere.