evaluate-sinh0sinhleft0right-given-the-definition-of-the-hyperbolic-sine-functio

Question

Evaluate $\sinh\left(0\right)$ given that the definition of the hyperbolic sine function is, $\sinh\left(x\right)=\frac{e^{x}-e^{-x}}{2}$ , and sketch a plausible graph for $y=\sinh(x)$ .

Accepted Answer

$\sinh\left(0\right)=0$

Graph of y=sinh(x) with a curve approaching the origin from both sides.

Answer

$\sinh\left(0\right)=0$

Graph of y=sinh(x) showing the curve passing through the origin.

Answer

$\sinh\left(0\right)=0$

Graph of y=sinh(x) depicting a U-shaped curve centered at the origin.

Answer

$\sinh\left(0\right)=0$

Graph of y=sinh(x) showing a downward opening curve centered at the origin.

Evaluate sinh(0)\sinh\left(0\right)sinh(0) given that the definition of the hyperbolic sine function is, sinh(x)=ex−e−x2\sinh\left(x\right)=\frac{e^{x}-e^{-x}}{2}sinh(x)=2ex−e−x, and sketch a plausible graph for y=sinh(x)y=\sinh(x)y=sinh(x).

Evaluate $\sinh\left(0\right)$ given that the definition of the hyperbolic sine function is, $\sinh\left(x\right)=\frac{e^{x}-e^{-x}}{2}$ , and sketch a plausible graph for $y=\sinh(x)$ .