Solve the equation 9 x − 5 = 102 9^{x-5}=102 9 x − 5 = 102 for x x x .

x = ln ⁡ 102 ln ⁡ 9 + 5 x=\frac{\ln102}{\ln9}+5 x = l n 9 l n 102 + 5

x = ln ⁡ 9 ln ⁡ 102 + 5 x=\frac{\ln9}{\ln102}+5 x = l n 102 l n 9 + 5

x = ln ⁡ 9 ln ⁡ 102 − 5 x=\frac{\ln9}{\ln102}-5 x = l n 102 l n 9 − 5

x = ln ⁡ 102 ln ⁡ 9 − 5 x=\frac{\ln102}{\ln9}-5 x = l n 9 l n 102 − 5

0. Functions - Part 2 of 2

0. Functions / Exponential Functions / Problem 6

Problem 6

Solve the equation $9^{x-5}=102$ for $x$ .

$x=\frac{\ln9}{\ln102}+5$

$x=\frac{\ln9}{\ln102}-5$

$x=\frac{\ln102}{\ln9}+5$

$x=\frac{\ln102}{\ln9}-5$