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Multiple Choice
Two hoses have been connected together. The first hose has a diameter of 4 cm, and the second has a diameter of If the water exits the narrower hose at a speed of , how quickly is the water moving inside the wider hose?
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Verified step by step guidance
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Identify the principle to use: This problem involves fluid flow through hoses of different diameters, so we will use the principle of conservation of mass, specifically the equation of continuity for incompressible fluids.
Write the equation of continuity: The equation is A1 * v1 = A2 * v2, where A1 and A2 are the cross-sectional areas of the wider and narrower hoses, respectively, and v1 and v2 are the velocities of the water in the wider and narrower hoses, respectively.
Calculate the cross-sectional areas: Use the formula for the area of a circle, A = π * (d/2)^2, where d is the diameter. For the wider hose, d = 4 cm, and for the narrower hose, d = 2.5 cm.
Substitute the known values into the equation of continuity: You know the velocity in the narrower hose (v2 = 3.4 m/s) and the diameters of both hoses. Substitute these into the equation A1 * v1 = A2 * v2 to solve for v1, the velocity in the wider hose.
Solve for v1: Rearrange the equation to find v1 = (A2 * v2) / A1. Calculate the areas using the diameters, substitute them into the equation, and solve for v1 to find the velocity of the water in the wider hose.