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Multiple Choice
Io and Ganymede are two of Jupiter's four Galilean moons. Io orbits at an average distance of 422,000km in 1.77 days. What is Ganymede's average orbital distance (in km), if it takes 4 times longer to orbit Jupiter?
A
670,000
B
1,063,000 km
C
167,000
D
844,000
Verified step by step guidance
1
Understand that the problem involves Kepler's Third Law, which states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
Identify the given values for Io: its orbital period (T1) is 1.77 days and its average orbital distance (a1) is 422,000 km.
Recognize that Ganymede's orbital period (T2) is 4 times that of Io, so T2 = 4 * 1.77 days.
Apply Kepler's Third Law: (T1^2 / a1^3) = (T2^2 / a2^3), where a2 is Ganymede's average orbital distance.
Rearrange the equation to solve for a2: a2 = ((T2^2 / T1^2) * a1^3)^(1/3). Substitute the known values to find a2.