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Multiple Choice
A gas with an initial volume of 0.2 m3 is heated at constant volume, and the pressure increases from 2×105 Pa to 5×105. Then, it compresses at constant pressure until it reaches a final volume of 0.12 m3. Draw the two processes in the PV diagram below and find the total work done by the gas.
A
- 1.6 × 104 J
B
4 × 104 J
C
0 J
D
- 4 × 104 J
Verified step by step guidance
1
Step 1: Begin by plotting the initial state of the gas on the PV diagram. The initial volume is 0.2 m³ and the initial pressure is 2×10^5 Pa. Mark this point on the graph.
Step 2: Since the gas is heated at constant volume, the volume remains at 0.2 m³ while the pressure increases to 5×10^5 Pa. Draw a vertical line upwards from the initial point to represent this process.
Step 3: Next, the gas compresses at constant pressure. This means the pressure remains at 5×10^5 Pa while the volume decreases to 0.12 m³. Draw a horizontal line to the left from the end of the vertical line to the new volume.
Step 4: To find the total work done by the gas, recall that work done at constant pressure is given by the formula W = PΔV, where ΔV is the change in volume. Since the first process is at constant volume, no work is done during that process.
Step 5: Calculate the work done during the compression at constant pressure. Use the formula W = P(V_final - V_initial) with P = 5×10^5 Pa, V_initial = 0.2 m³, and V_final = 0.12 m³. Substitute these values into the formula to find the work done.