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Multiple Choice
An AC emf source is given by. What is the instantaneous emf of this source at ?
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Verified step by step guidance
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Start by identifying the given AC emf equation: ε = (170V)cos{2π(60Hz)t}. This represents the instantaneous emf as a function of time.
Recognize that the equation is in the form ε = ε₀ cos(ωt), where ε₀ is the peak emf (170 V), and ω is the angular frequency. The angular frequency ω is given by ω = 2πf, where f is the frequency (60 Hz).
Substitute the given time t = 97 ms into the equation. First, convert 97 ms to seconds: t = 97 ms = 0.097 s.
Calculate the argument of the cosine function: ωt = 2π(60Hz)(0.097s). This will give you the angle in radians that you need to evaluate the cosine function.
Evaluate the cosine function at the calculated angle and multiply by the peak emf (170 V) to find the instantaneous emf at t = 97 ms. This will give you the value of the emf at that specific time.