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Multiple Choice
Some trainyards have very large horizontal disks that engines can drive onto, which then rotate to turn the engine around to face the opposite direction. Suppose the train engine is 12 m long and centered at the disk's axis. A 500 N force is applied 5.0 m from the center of the engine, with a rope that makes a angle with the side of the engine. What magnitude torque is being applied to the train engine?
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Verified step by step guidance
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Identify the formula for torque: Torque (τ) is given by the equation τ = r * F * sin(θ), where r is the distance from the pivot point to the point where the force is applied, F is the magnitude of the force, and θ is the angle between the force and the lever arm.
Determine the values given in the problem: The force (F) applied is 500 N, the distance (r) from the center of the engine to the point where the force is applied is 5.0 m, and the angle (θ) between the force and the side of the engine is 35 degrees.
Convert the angle from degrees to radians if necessary, as some calculations might require it. However, for this problem, you can use the angle in degrees directly in the sine function.
Substitute the known values into the torque formula: τ = 5.0 m * 500 N * sin(35°).
Calculate the sine of 35 degrees and multiply the values to find the magnitude of the torque. This will give you the torque applied to the train engine.