Open Question
(II) A 95-kg fullback is running at 3.0 m/s to the east and is stopped in 0.75 s by a head-on tackle by a tackler running due west. Calculate
(d) the average force exerted on the tackler.
11. Momentum & Impulse
Intro to Impulse
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You catch a 0.6 kg ball initially moving with 10 m/s. Calculate the impulse delivered to the ball during the catch.
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Verified step by step guidance1
Identify the given values: the mass of the ball \( m = 0.6 \text{ kg} \) and its initial velocity \( v_i = 10 \text{ m/s} \).
Understand that impulse \( J \) is defined as the change in momentum of an object. The formula for impulse is \( J = \Delta p = m \cdot \Delta v \), where \( \Delta v \) is the change in velocity.
Since the ball is caught, its final velocity \( v_f \) is 0 m/s. Therefore, the change in velocity \( \Delta v = v_f - v_i = 0 - 10 \text{ m/s} \).
Substitute the values into the impulse formula: \( J = 0.6 \text{ kg} \times (-10 \text{ m/s}) \).
Calculate the impulse \( J \) to find the magnitude of the impulse delivered to the ball during the catch.
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