Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
You have a block of ice at 0°C. Heat is added to the ice, causing an increase in entropy of 120J/K. How much ice melts into water in this process?
A
0.098 kg
B
0 kg
C
1.32×10-6 kg
D
1.47×105 kg
Verified step by step guidance
1
Identify the process: The problem involves the melting of ice at 0°C, which is a phase change process where heat is added to convert ice into water without changing temperature.
Understand the relationship between entropy change and heat: The change in entropy (ΔS) is related to the heat added (Q) during a phase change by the formula ΔS = Q/T, where T is the temperature in Kelvin.
Convert the temperature: Since the ice is at 0°C, convert this to Kelvin by adding 273.15, giving T = 273.15 K.
Use the formula to find the heat added: Rearrange the formula to find Q, the heat added, as Q = ΔS * T. Substitute ΔS = 120 J/K and T = 273.15 K into the equation.
Calculate the mass of ice melted: Use the latent heat of fusion for ice, L = 334,000 J/kg, to find the mass of ice melted. The mass m can be found using m = Q/L, where Q is the heat calculated in the previous step.