Open Question
(II) A 265-kg load is lifted 18.0 m vertically with an acceleration a = 0.140 g by a single cable. Determine
(a) the tension in the cable;
6. Intro to Forces (Dynamics)
Vertical Forces & Acceleration
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Fernanda is standing on a scale while riding an elevator. If the scale reads while the elevator is accelerating upwards at , what is Fernanda's mass?
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Verified step by step guidance1
Start by identifying the forces acting on Fernanda. The scale reading indicates the normal force, which is the force exerted by the scale on Fernanda. This force is equal to the apparent weight when the elevator is accelerating.
Use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration: .
Consider the forces in the vertical direction. The net force is the difference between the normal force (scale reading) and the gravitational force (true weight): , where is the normal force and is the weight.
Express the weight in terms of mass and gravitational acceleration: , where is the acceleration due to gravity (approximately ).
Substitute the known values into the equation: . Solve for using the given normal force and acceleration .
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