Open Question
(II) The position of an object along a straight tunnel as a function of time is plotted in Fig. 2–40. What is its average velocity
(d) between t = 25.0 s and t = 30.0 s
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2. 1D Motion / Kinematics
Average Velocity
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You walk to the right at 3m/s for 8s, then turn around and walk backwards at 2m/s for some unknown time. You end up 16m to the right from where you started. How long did you walk backwards?
A
8.0 s
B
2.3 s
C
16 s
D
4.0 s
Verified step by step guidance1
First, calculate the distance traveled while walking to the right. Use the formula for distance: \( \text{distance} = \text{speed} \times \text{time} \). Here, the speed is 3 m/s and the time is 8 s.
Substitute the values into the formula: \( \text{distance} = 3 \text{ m/s} \times 8 \text{ s} \). This gives the distance traveled to the right.
Next, consider the total displacement from the starting point, which is 16 m to the right. This displacement is the result of walking to the right and then backwards.
Let \( t \) be the time walked backwards at 2 m/s. The distance walked backwards can be expressed as \( \text{distance} = 2 \text{ m/s} \times t \).
Set up the equation for total displacement: \( 3 \times 8 - 2 \times t = 16 \). Solve this equation for \( t \) to find the time walked backwards.
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