A lightning bolt hits the ground carrying a current of 3 × 10 4 A. If the strike lasts 50 ms, how much charge enters the ground?

Hey, guys. So we have this, problem involving a lightning bolt that's hitting the ground. It's carrying some amount of current, and the lightning bolt discharges in a certain amount of time. So we're supposed to figure out how much charge is entering the ground. Well, that's pretty straightforward. What's the relationship between charge, time and current? So if we're looking for q, we have to relate it back to I equals delta q over delta t. The amount of charge that's going into some place in a certain amount of time. Now we have what the current is, and we have what the time is. So we just go ahead and rearrange and then solve for delta q. So I times delta t is going to be delta q. So all you have to do is just multiply these 2, just make sure they're in the right units. So the current is equal to 3 times 10 to the 4th amps, and the time was equal to 50 milliseconds. So that's 50 times 10 to the minus 3, or you could have written this as 0.0 5 or something like that. Right? So if you just go ahead and multiply these out, you should get 1.5 times 10 to the 3rd, and that's gonna be in coulombs. So in other words, that's 1500 coulombs. That's a lot of charge entering in a very, very small amount of time. So current discharges is a lot amount of lightning or sorry, lightning discharges a lot amount of current in a short amount of time. Alright? Anyway, that's the answer for this. Both could be represented like this. Let me know if you guys have any questions.