A chemist wants to make 3.00 L of a 0.250 M NaNO 3 solution. What mass of NaNO 3 (in g) should the chemist use?

everyone to hear what? Ask. Chocolate and Masterman using iodide That has made it to prepare 0.2 l A 4.59 Mueller of magnesium iodide solution. Recall that polarity. It was moss of solute. But by leaders of solution. Since we're giving the volume and the clarity you can use the maturity equation to solve for moles We have 4.59 Mueller. There's going to be equal to X Divided by 0. leaders. So if you must have 4.59 my word Times 0.2 leaders. Is that equal to X? I'm gonna get X. Is equal to 0.918 moles. And now since we have moles we can convert from moles of magnesium iodide to find grams of magnesium iodide 0. 18 bob a magnesium iodine. And in one mall mechanism I died we had the molar mass which we need to find. The molar mass is equal to the math of Magnesium which is .305g plus two Because there's two iodine comes a mass of iodine Which is .904 gramps. And this will give us 278 113 grams of magnesium. I died. So now this will give us 255 grams. Thanks for watching my video and I hope it was helpful

Ch.5 - Introduction to Solutions and Aqueous Solutions

All textbooks

Tro 6th Edition

Ch.5 - Introduction to Solutions and Aqueous Solutions

Problem 33

Chapter 5, Problem 33

A chemist wants to make 3.00 L of a 0.250 M NaNO₃ solution. What mass of NaNO₃ (in g) should the chemist use?

Verified step by step guidance

Determine the molarity formula: Molarity (M) is defined as the number of moles of solute per liter of solution. The formula is M = \frac{n}{V}, where n is the number of moles and V is the volume in liters.

Rearrange the formula to solve for the number of moles of NaNO_3 needed: n = M \times V.

Substitute the given values into the equation: M = 0.250 \text{ M} and V = 3.00 \text{ L}. Calculate the number of moles of NaNO_3 required.

Use the molar mass of NaNO_3 to convert moles to grams. The molar mass of NaNO_3 is approximately 85.00 \text{ g/mol}.

Multiply the number of moles by the molar mass to find the mass of NaNO_3 needed in grams.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.

Video duration:

Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molarity (M)

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in moles per liter (mol/L). In this question, the desired molarity of the NaNO3 solution is 0.250 M, indicating that there are 0.250 moles of NaNO3 in every liter of the solution.

Moles and Mass Relationship

The relationship between moles and mass is governed by the formula: mass = moles × molar mass. To find the mass of NaNO3 needed, the chemist must first calculate the total number of moles required for the 3.00 L solution and then multiply that by the molar mass of NaNO3, which is approximately 85.00 g/mol.

Dilution and Solution Preparation

Preparing a solution involves accurately measuring and mixing a solute with a solvent to achieve a desired concentration. In this case, the chemist needs to ensure that the calculated mass of NaNO3 is properly dissolved in enough water to make a total volume of 3.00 L, ensuring the final concentration is 0.250 M.