Skip to main content
Pearson+ LogoPearson+ Logo
Ch.20 - Electrochemistry
All textbooksTro 6th EditionCh.20 - ElectrochemistryProblem 74
Chapter 20, Problem 74

Calculate the equilibrium constant for the reaction between Fe2+(aq) and Zn(s) (at 25 °C).

Verified step by step guidance
1
Identify the half-reactions involved in the process. For the reaction between Fe2+(aq) and Zn(s), the half-reactions are: Zn(s) → Zn2+(aq) + 2e- (oxidation) and Fe2+(aq) + 2e- → Fe(s) (reduction).
Write the balanced overall reaction by combining the half-reactions. Ensure that the electrons lost in the oxidation half-reaction are equal to the electrons gained in the reduction half-reaction. The overall reaction is: Zn(s) + Fe2+(aq) → Zn2+(aq) + Fe(s).
Use the standard reduction potentials for each half-reaction to calculate the standard cell potential (E°cell). The standard reduction potential for Zn2+/Zn is -0.76 V and for Fe2+/Fe is -0.44 V. Calculate E°cell using the formula: E°cell = E°cathode - E°anode.
Calculate the equilibrium constant (K) using the Nernst equation at standard conditions (25 °C, 1 M concentration for all aqueous species). The Nernst equation at standard conditions simplifies to: \( \Delta G^\circ = -nFE^\circ_{\text{cell}} \) and \( \Delta G^\circ = -RT \ln K \).
Solve for K using the relationship between Gibbs free energy and the equilibrium constant. Rearrange the equation to find K: \( K = e^{-\frac{nFE^\circ_{\text{cell}}}{RT}} \), where n is the number of moles of electrons transferred in the balanced equation, F is the Faraday constant (96485 C/mol), R is the gas constant (8.314 J/mol·K), and T is the temperature in Kelvin.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
6m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Equilibrium Constant (K)

The equilibrium constant (K) is a numerical value that expresses the ratio of the concentrations of products to reactants at equilibrium for a given chemical reaction. It is temperature-dependent and provides insight into the extent of a reaction; a large K indicates a reaction that favors products, while a small K suggests reactants are favored.
Recommended video:
Guided course
01:14
Equilibrium Constant K

Redox Reactions

Redox (reduction-oxidation) reactions involve the transfer of electrons between species, resulting in changes in oxidation states. In the context of the given reaction, Fe2+ is reduced to Fe, while Zn is oxidized to Zn2+. Understanding the electron transfer is crucial for determining the direction and extent of the reaction.
Recommended video:
Guided course
03:12
Identifying Redox Reactions

Standard Electrode Potentials

Standard electrode potentials are measured voltages that indicate the tendency of a species to be reduced or oxidized under standard conditions. These values can be used to calculate the overall cell potential for redox reactions, which in turn helps in determining the equilibrium constant using the Nernst equation.
Recommended video:
Guided course
01:27
Standard Cell Potential
Related Practice
Textbook Question

Use tabulated electrode potentials to calculate 𝛥𝐺rxn° for each reaction at 25 °C. c. Br2(l) + 2Cl–(aq) → 2 Br–(aq) + Cl2(g)

Textbook Question

Calculate the equilibrium constant for each of the reactions in Problem 70.

Textbook Question

A voltaic cell employs the following redox reaction: Sn2+(aq) + Mn(s) → Sn(s) + Mn2+(aq) Calculate the cell potential at 25 °C under each set of conditions. c. [Sn2+] = 2.00 M; [Mn2+] = 0.0100 M