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Ch.1 - Matter, Measurement & Problem Solving
Chapter 1, Problem 67

Glycerol is a syrupy liquid often used in cosmetics and soaps. A 3.25 L sample of pure glycerol has a mass of 4.10×103 g. What is the density of glycerol in g/cm3?

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1
Convert the volume from liters to cubic centimeters (cm^3) using the conversion factor: 1 L = 1000 cm^3.
Calculate the density using the formula: \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \).
Substitute the given mass (4.10 \times 10^3 \text{ g}) and the converted volume into the density formula.
Simplify the expression to find the density in g/cm^3.
Ensure the units are consistent and the final density is expressed in g/cm^3.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Density

Density is defined as the mass of a substance divided by its volume. It is typically expressed in units such as grams per cubic centimeter (g/cm³) or kilograms per liter (kg/L). Understanding density is crucial for determining how much mass is contained in a given volume of a substance, which is essential in various applications, including chemistry and material science.
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Mass and Volume

Mass is a measure of the amount of matter in an object, usually measured in grams (g) or kilograms (kg). Volume, on the other hand, is the amount of space that a substance occupies, commonly measured in liters (L) or cubic centimeters (cm³). In the context of calculating density, both mass and volume are necessary components, as density is derived from their relationship.
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Unit Conversion

Unit conversion is the process of converting a quantity expressed in one set of units to another. In this question, it is important to ensure that the volume of glycerol is expressed in cubic centimeters (cm³) to match the density units of g/cm³. Understanding how to convert between liters and cubic centimeters (1 L = 1000 cm³) is essential for accurate calculations in chemistry.
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