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Ch.8 - Covalent Compounds: Bonding Theories and Molecular Structure
Chapter 8, Problem 126

Bond vibrations for the symmetric and asymmetric stretch in methane are illustrated below. Decide whether each vibration will result in the absorption of IR radiation. Arrows indicate the movement of atoms during the vibration.Illustration of symmetric and asymmetric bond vibrations in methane with arrows indicating atom movement.

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Identify the type of bond vibrations shown in the image: symmetric stretch and asymmetric stretch.
Understand that for a vibration to result in the absorption of IR radiation, there must be a change in the dipole moment of the molecule.
Analyze the symmetric stretch: all bonds are stretching and compressing in unison, which typically does not change the dipole moment significantly.
Analyze the asymmetric stretch: bonds are stretching and compressing in an unsynchronized manner, which usually results in a change in the dipole moment.
Conclude that the asymmetric stretch will result in the absorption of IR radiation, while the symmetric stretch will not.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Infrared (IR) Spectroscopy

Infrared spectroscopy is a technique used to identify molecular vibrations that occur when molecules absorb infrared light. Molecules can absorb IR radiation if the vibration results in a change in the dipole moment. This property is crucial for determining which molecular vibrations will lead to IR absorption.
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Molecular Vibrations

Molecular vibrations refer to the oscillations of atoms within a molecule around their equilibrium positions. These vibrations can be classified into different types, such as stretching (change in bond length) and bending (change in bond angles). Understanding these vibrations helps predict how molecules interact with IR radiation.
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Molecular Polarity

Symmetric vs. Asymmetric Stretching

Symmetric stretching occurs when atoms in a molecule move in and out together, maintaining the center of mass, while asymmetric stretching involves atoms moving in opposite directions. In the context of IR absorption, symmetric stretches typically do not result in a change in dipole moment, whereas asymmetric stretches often do, making them more likely to absorb IR radiation.
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Related Practice
Textbook Question

Cyclooctatetraene dianion, C8H82-, is an organic ion with the structure shown. Considering only the p bonds and not the s bonds, cyclooctatetraene dianion can be described by the following energy diagrams of its p molecular orbitals:

(b) Three of the p molecular orbitals are bonding, three are antibonding, and two are nonbonding, meaning that they have the same energy level as isolated p orbitals. Which is which?

Textbook Question

Cyclooctatetraene dianion, C8H82-, is an organic ion with the structure shown. Considering only the p bonds and not the s bonds, cyclooctatetraene dianion can be described by the following energy diagrams of its p molecular orbitals:

(c) Complete the MO energy diagram by assigning the appropriate numbers of p electrons to the various molecular orbitals, indicating the electrons using up/down arrows 1c T2.

Textbook Question
The water molecule has similar bond vibrations to carbon dioxide. Decide whether the symmetric, asymmetric, and bending vibrations in water will result in the absorption of IR radiation.
Textbook Question
Values of Ea = 6.3 kJ>mol and A = 6.0 * 108>1M # s2 have been measured for the bimolecular reaction: NO1g2 + F21g2S NOF1g2 + F1g2 (b) The product of the reaction is nitrosyl fluoride. Its formula is usually written as NOF, but its structure is actually ONF. Is the ONF molecule linear or bent?
Textbook Question
(b) When xenon absorbs 801 kJ/mol of energy, it is excited into a higher-energy state in which the outermost elec-tron has been promoted to the next available subshell. Write the electron configuration for this excited xenon.
Textbook Question
The equilibrium constant Kc for the gas-phase thermal decom-position of cyclopropane to propene is 1.0 * 105 at 500 K:

(e) Why is cyclopropane so reactive? (Hint: Consider the hybrid orbitals used by the C atoms.)