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Ch.13 - Solutions & Their Properties
Chapter 13, Problem 11

Acetone, C3H6O, and ethyl acetate, C4H8O2, are organic liquids often used as solvents. At 30 °C, the vapor pressure of acetone is 285 mm Hg, and the vapor pressure of ethyl acetate is 118 mm Hg. What is the vapor pressure in mm Hg at 30 °C of a solution prepared by dissolving 25.0 g of acetone in 25.0 g of ethyl acetate?

Verified step by step guidance
1
Step 1: Calculate the number of moles of acetone (C_3H_6O) using its molar mass. The molar mass of acetone is approximately 58.08 g/mol.
Step 2: Calculate the number of moles of ethyl acetate (C_4H_8O_2) using its molar mass. The molar mass of ethyl acetate is approximately 88.12 g/mol.
Step 3: Determine the mole fraction of acetone in the solution. The mole fraction is calculated by dividing the moles of acetone by the total moles of both acetone and ethyl acetate.
Step 4: Determine the mole fraction of ethyl acetate in the solution. The mole fraction is calculated by dividing the moles of ethyl acetate by the total moles of both acetone and ethyl acetate.
Step 5: Use Raoult's Law to calculate the total vapor pressure of the solution. Raoult's Law states that the vapor pressure of the solution is the sum of the partial pressures of each component, which are calculated by multiplying the mole fraction of each component by its pure vapor pressure.

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Vapor Pressure

Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid or solid phase at a given temperature. It reflects the tendency of molecules to escape from the liquid phase into the vapor phase. The higher the vapor pressure, the more volatile the substance. In this question, the vapor pressures of acetone and ethyl acetate are crucial for determining the overall vapor pressure of the solution.
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Raoult's Law

Raoult's Law states that the vapor pressure of a solvent in a solution is directly proportional to the mole fraction of the solvent in the solution. This law is essential for calculating the vapor pressure of a mixture of solvents, as it allows us to predict how the presence of one solvent affects the vapor pressure of another. In this case, it will help determine the vapor pressure of the solution formed by mixing acetone and ethyl acetate.
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Mole Fraction

Mole fraction is a way of expressing the concentration of a component in a mixture, defined as the number of moles of that component divided by the total number of moles of all components in the mixture. It is a dimensionless quantity that helps in applying Raoult's Law to find the vapor pressure of each component in a solution. Calculating the mole fractions of acetone and ethyl acetate is necessary to apply Raoult's Law in this scenario.
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Related Practice
Textbook Question
The molarity of a solution of sodium acetate (CH3COONa) at 20 C is 7.5 M. Use the graph showing the solubility of sodium acetate as a function of temperature to describe the solution. The solution is . (LO 13.7, 13.8)

(a) Saturated (b) Unsaturated (c) Supersaturated (d) Colloidal
Textbook Question
A scuba diver is breathing compressed air that is 21% (by volume) oxygen at a depth of 66 ft. beneath the surface. The total pressure at this depth is 3.0 atm. The Henry's law constant (k) for O2 in water at a normal body temperature (37 °C ) is 1.93 * 10-3 mol>(L atm). What is the solubilityof O2 in the blood of the diver at 66 ft. beneath the surface?(LO 13.9)(a) 1.22 * 10-3 M (b) 2.76 * 10-2 M(c) 1.22 * 10-1 M (d) 2.76 * 10-1 M
Textbook Question
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Textbook Question
12. A solution contains 4.08 g of chloroform 1CHCl32 and 9.29 g of acetone 1CH3COCH32. The vapor pressures at 35 °C of pure chloroform and pure acetone are 295 torr and 332 torr, respectively. Assuming ideal behavior, calculate the vapor pressure above the solution. (LO 13.12) (a) 256 torr (b) 314 torr (c) 325 torr (d) 462 torr
Textbook Question
How many kilograms of ethylene glycol (automobile anti- freeze, C2H6O2) dissolved in 3.55 kg of water are needed to lower the freezing point of water in an automobile radiator to - 22.0 °C? The molal freezing point depression constant for water is Kf = 1.86 1°C kg2>mol. (LO 13.13) (a) 0.865 kg (b) 0.0420 kg (c) 9.01 kg (d) 2.61 kg