Identify the precipitate (if any) that forms when the following solutions are mixed, and write a balanced equation for each reaction. b. KOH and Cu(NO3)2
Ch.4 - Reactions in Aqueous Solution
Chapter 4, Problem 26a
Write balanced net ionic equations for the reactions that occur in each of the following cases. Identify the spectator ion or ions in each reaction. a. Cr2(SO4)3(ππ)+(NH4)2CO3(ππ)βΆ

1
Identify the ions present in each compound: \( \text{Cr}_2(\text{SO}_4)_3 \) dissociates into \( 2\text{Cr}^{3+} \) and \( 3\text{SO}_4^{2-} \); \( (\text{NH}_4)_2\text{CO}_3 \) dissociates into \( 2\text{NH}_4^+ \) and \( \text{CO}_3^{2-} \).
Determine the possible products of the reaction: \( \text{Cr}_2(\text{CO}_3)_3 \) and \( \text{(NH}_4)_2\text{SO}_4 \).
Check the solubility of the products: \( \text{Cr}_2(\text{CO}_3)_3 \) is insoluble, forming a precipitate, while \( \text{(NH}_4)_2\text{SO}_4 \) is soluble.
Write the balanced molecular equation: \( \text{Cr}_2(\text{SO}_4)_3(\text{aq}) + 3(\text{NH}_4)_2\text{CO}_3(\text{aq}) \rightarrow \text{Cr}_2(\text{CO}_3)_3(\text{s}) + 3\text{(NH}_4)_2\text{SO}_4(\text{aq}) \).
Write the net ionic equation by removing spectator ions: \( 2\text{Cr}^{3+}(\text{aq}) + 3\text{CO}_3^{2-}(\text{aq}) \rightarrow \text{Cr}_2(\text{CO}_3)_3(\text{s}) \). Spectator ions are \( \text{NH}_4^+ \) and \( \text{SO}_4^{2-} \).

Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
7mWas this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Net Ionic Equations
Net ionic equations represent the actual chemical species that participate in a reaction, excluding spectator ions. To write a net ionic equation, one must first write the balanced molecular equation, then dissociate all soluble ionic compounds into their constituent ions, and finally eliminate the spectator ions that do not change during the reaction.
Recommended video:
Guided course
Net Ionic Equations
Spectator Ions
Spectator ions are ions that exist in the same form on both the reactant and product sides of a chemical equation. They do not participate in the actual chemical reaction and can be removed from the net ionic equation. Identifying spectator ions is crucial for simplifying the equation to focus on the species that undergo a change.
Recommended video:
Guided course
Ion Formation
Solubility Rules
Solubility rules are guidelines that help predict whether an ionic compound will dissolve in water. These rules indicate which ions are generally soluble or insoluble in aqueous solutions, which is essential for determining the reactants and products in a reaction, as well as for identifying the ions that will remain in solution versus those that will precipitate.
Recommended video:
Guided course
Solubility Rules
Related Practice
Textbook Question
Textbook Question
Which ions remain in solution, unreacted, after each of the following pairs of solutions is mixed? (a) potassium carbonate and magnesium sulfate
Textbook Question
Which ions remain in solution, unreacted, after each of the following pairs of solutions is mixed? (c) ammonium phosphate and calcium chloride
Textbook Question
Write balanced net ionic equations for the reactions that occur in each of the following cases. Identify the spectator ion or ions in each reaction. c. Fe(NO3)2(ππ)+KOH(ππ)βΆ
Textbook Question
Separate samples of a solution of an unknown ionic compound are treated with dilute AgNO3, Pb1NO322, and BaCl2. Precipitates form in all three cases. Which of the following could be the anion of the unknown salt: Br-, CO32-, NO3-?
2
views