From each of the following pairs of substances, use data in Appendix E to choose the one that is the stronger reducing agent: (d) BrO3-1aq2 or IO3-1aq2
Ch.20 - Electrochemistry
Chapter 20, Problem 60
Using the standard reduction potentials listed in Appendix E, calculate the equilibrium constant for each of the following reactions at 298 K: (a) Cu(s) + 2 Ag+(aq) → Cu2+(aq) + 2 Ag(s) (b) 3 Ce4+(aq) + Bi(s) + H2O(l) → 3 Ce3+(aq) + BiO+(aq) + 2 H+(aq) (c) N2H5+(aq) + 4 Fe(CN)6^3- (aq) → N2(g) + 5 H+(aq) + 4 Fe(CN)6^4-(aq)

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Step 1: Identify the half-reactions for each redox reaction and write their standard reduction potentials (E°) from Appendix E.
Step 2: For each reaction, determine the oxidation and reduction half-reactions and calculate the standard cell potential (E°cell) using the formula: E°cell = E°(reduction) - E°(oxidation).
Step 3: Use the Nernst equation to relate the standard cell potential to the equilibrium constant (K) at 298 K: E°cell = (RT/nF) * ln(K), where R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin, n is the number of moles of electrons transferred, and F is Faraday's constant (96485 C/mol).
Step 4: Rearrange the Nernst equation to solve for the equilibrium constant (K): K = exp((nFE°cell)/(RT)).
Step 5: Substitute the values for n, F, R, T, and E°cell into the equation to calculate the equilibrium constant (K) for each reaction.
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Standard Reduction Potentials
Standard reduction potentials are measured voltages that indicate the tendency of a chemical species to gain electrons and be reduced. Each half-reaction has a specific potential, and these values are typically listed in a standard table. The more positive the potential, the greater the species' ability to be reduced. These values are crucial for calculating the overall cell potential and determining the direction of electron flow in redox reactions.
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Standard Reduction Potentials
Nernst Equation
The Nernst equation relates the cell potential of an electrochemical reaction to the concentrations of the reactants and products at non-standard conditions. It is expressed as E = E° - (RT/nF) ln(Q), where E° is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, n is the number of moles of electrons transferred, F is Faraday's constant, and Q is the reaction quotient. This equation is essential for calculating the equilibrium constant from the standard potentials.
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Equilibrium Constant (K)
The equilibrium constant (K) quantifies the ratio of the concentrations of products to reactants at equilibrium for a given reaction at a specific temperature. It is derived from the relationship between the standard cell potential and the Gibbs free energy change. A larger K value indicates a greater tendency for the reaction to favor products, while a smaller K suggests a preference for reactants. Understanding K is vital for predicting the extent of reactions and their favorability.
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Related Practice
Textbook Question
Textbook Question
Using the standard reduction potentials listed in Appendix E, calculate the equilibrium constant for each of the following reactions at 298 K:
(a) Fe(s) + Ni2+(aq) → Fe2+(aq) + Ni(s)
(b) Co(s) + 2 H+(aq) → Co2+(aq) + H2(g)
(c) 10 Br-(aq) + 2 MnO4-(aq) + 16 H+(aq) → 2 Mn2+(aq) + 8 H2O(l) + 5 Br2(l)
Textbook Question
A cell has a standard cell potential of +0.177 V at 298 K. What is the value of the equilibrium constant for the reaction
(a) if n = 1?
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Textbook Question
A cell has a standard cell potential of +0.177 V at 298 K. What is the value of the equilibrium constant for the reaction (b) if n = 2? (c) if n = 3?
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Textbook Question
At 298 K a cell reaction has a standard cell potential of +0.17 V. The equilibrium constant for the reaction is 5.5 × 105. What is the value of n for the reaction?