A solution of 100.0 mL of 0.200 M KOH is mixed with a solution of 200.0 mL of 0.150 M NiSO 4 . (a) Write the balanced chemical equation for the reaction that occurs.

Hi everyone here we have a question asking us to write the balanced chemical reaction for the reaction of 120.5 ml of 0.150 Molar potassium hydroxide 250 ml of 0. moller copper nitrate. So we're going to start out with our potassium hydroxide plus our copper nitrate. And now we're going to displace these. So our potassium is going to go with our nitrate, potassium has a charge of plus one nitrate has a charge of minus one. So those will cancel out and it will just be K N. 03. And now our copper Is going to go with our hydroxide. Copper has a charge of two plus Hydroxide has a charge of -1. So where you're going to criss cross those to get copper and two hydroxide. So that is forming copper hydroxide plus potassium nightshade. And now we need to balance this. So if we look on the left we only have one hydrogen and on the right we have two. So we're going to fix that by putting a two in front of our potassium hydroxide. And now if we look on our reactive side we have two potassium and only one on our product side. So we're going to fix that by putting a two in front of our potassium nitrate. And now we are all balanced and that is our final equation. Thank you for watching. Bye

Ch.4 - Reactions in Aqueous Solution

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Brown 14th Edition

Ch.4 - Reactions in Aqueous Solution

Problem 87a

Chapter 4, Problem 87a

A solution of 100.0 mL of 0.200 M KOH is mixed with a solution of 200.0 mL of 0.150 M NiSO₄. (a) Write the balanced chemical equation for the reaction that occurs.

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Identify the reactants: KOH and NiSO_4.

Determine the products of the reaction: KOH is a strong base and NiSO_4 is a salt, so they will undergo a double displacement reaction to form Ni(OH)_2 and K_2SO_4.

Write the unbalanced chemical equation: KOH + NiSO_4 -> Ni(OH)_2 + K_2SO_4.

Balance the chemical equation by ensuring the same number of each type of atom on both sides of the equation.

The balanced chemical equation is: 2 KOH + NiSO_4 -> Ni(OH)_2 + K_2SO_4.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Acid-Base Reactions

Acid-base reactions involve the transfer of protons (H+) between reactants. In this case, KOH acts as a strong base, providing hydroxide ions (OH-) that can react with metal cations. Understanding the nature of acids and bases is crucial for predicting the products of the reaction.

Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions based on balanced equations. It allows us to determine the proportions of KOH and NiSO4 that will react, which is essential for writing the balanced chemical equation and understanding the quantities involved.

Precipitation Reactions

Precipitation reactions occur when two soluble salts react to form an insoluble compound, or precipitate. In this scenario, the reaction between KOH and NiSO4 may produce nickel hydroxide (Ni(OH)2), which is insoluble in water. Recognizing the solubility rules helps in identifying the products of the reaction.

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Related Practice

Textbook Question

A 4.36-g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of water. An acid–base indicator is added, and the resulting solution is titrated with 2.50 M HCl(aq) solution. The indicator changes color, signaling that the equivalence point has been reached, after 17.0 mL of the hydrochloric acid solution has been added. (a) What is the molar mass of the metal hydroxide?

Textbook Question

An 8.65-g sample of an unknown group 2 metal hydroxide is dissolved in 85.0 mL of water. An acid–base indicator is added and the resulting solution is titrated with 2.50 M HCl(aq) solution. The indicator changes color, signaling that the equivalence point has been reached, after 56.9 mL of the hydrochloric acid solution has been added. (a) What is the molar mass of the metal hydroxide? (b) What is the identity of the metal cation: Ca²⁺, Sr²⁺, or Ba²⁺?

Textbook Question

A solution of 100.0 mL of 0.200 M KOH is mixed with a solution of 200.0 mL of 0.150 M NiSO_4.(b) What precipitate forms?

Textbook Question

A solution of 100.0 mL of 0.200 M KOH is mixed with a solution of 200.0 mL of 0.150 M NiSO₄. (e) What is the concentration of each ion that remains in solution?

Textbook Question

A solution is made by mixing 1.5 g of LiOH and 23.5 mL of 1.000 M HNO₃. (b) Calculate the concentration of each ion remaining in solution.

A solution of 100.0 mL of 0.200 M KOH is mixed with a solution of 200.0 mL of 0.150 M NiSO4. (a) Write the balanced chemical equation for the reaction that occurs.

Verified video answer for a similar problem:

Key Concepts

Acid-Base Reactions

Stoichiometry

Precipitation Reactions

A solution of 100.0 mL of 0.200 M KOH is mixed with a solution of 200.0 mL of 0.150 M NiSO₄. (a) Write the balanced chemical equation for the reaction that occurs.