At 900 K, the following reaction has 𝐾𝑝 = 0.345: 2 SO2(𝑔) + O2(𝑔) ⇌ 2 SO3(𝑔) In an equilibrium mixture the partial pressures of SO2 and O2 are 0.135 atm and 0.455 atm, respectively. What is the equilibrium partial pressure of SO3 in the mixture?
Ch.15 - Chemical Equilibrium
Chapter 15, Problem 49
At 800 K, the equilibrium constant for the reaction I2(g) ⇌ 2 I(g) is Kc = 3.1 * 10^-5. If an equilibrium mixture in a 10.0-L vessel contains 2.67 * 10^-2 g of I(g), how many grams of I2 are in the mixture?

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Convert the mass of I(g) to moles using its molar mass. The molar mass of iodine (I) is approximately 126.90 g/mol.
Calculate the concentration of I(g) in moles per liter by dividing the moles of I(g) by the volume of the vessel in liters.
Use the equilibrium constant expression for the reaction: Kc = [I]^2 / [I2]. Rearrange this expression to solve for the concentration of I2.
Substitute the known values into the rearranged equilibrium expression to find the concentration of I2 in moles per liter.
Convert the concentration of I2 to grams using its molar mass (I2 has a molar mass of approximately 253.80 g/mol) and the volume of the vessel.
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Equilibrium Constant (Kc)
The equilibrium constant (Kc) is a numerical value that expresses the ratio of the concentrations of products to reactants at equilibrium for a given reaction at a specific temperature. For the reaction I2(g) ⇌ 2 I(g), Kc = [I]^2 / [I2]. A small Kc value, like 3.1 * 10^-5, indicates that at equilibrium, the concentration of reactants (I2) is much greater than that of products (I).
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Molar Mass and Conversion
To determine the amount of I2 in grams, it is essential to convert the mass of I(g) into moles using its molar mass. The molar mass of iodine (I) is approximately 126.9 g/mol. This conversion allows for the calculation of the concentration of I(g) in the equilibrium expression, which is necessary for finding the concentration of I2 using the equilibrium constant.
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Stoichiometry in Equilibrium
Stoichiometry involves the quantitative relationships between reactants and products in a chemical reaction. In this case, the stoichiometric coefficients indicate that for every mole of I2 produced, two moles of I(g) are formed. This relationship is crucial for calculating the amount of I2 present in the equilibrium mixture based on the amount of I(g) and the equilibrium constant.
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Related Practice
Textbook Question
Textbook Question
At 2000°C, the equilibrium constant for the reaction 2 NO(𝑔) ⇌ N2(𝑔) + O2(𝑔) is 𝐾𝑐 = 2.4×103. If the initial concentration of NO is 0.175 M, what are the equilibrium concentrations of NO, N2, and O2?
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Textbook Question
For the equilibrium Br2(𝑔) + Cl2(𝑔) ⇌ 2 BrCl(𝑔) at 400 K, 𝐾𝑐 = 7.0. If 0.25 mol of Br2 and 0.55 mol of Cl2 are introduced into a 3.0-L container at 400 K, what will be the equilibrium concentrations of Br2, Cl2, and BrCl?
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Textbook Question
At 373 K, 𝐾𝑝 = 0.416 for the equilibrium 2 NOBr(𝑔) ⇌ 2 NO(𝑔) + Br2(𝑔) If the pressures of NOBr(𝑔) and NO(𝑔) are equal, what is the equilibrium pressure of Br2(𝑔)?