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Based on the VSEPR theory, determine whether XeCl4 or CCl4 will have smaller Cl–X–Cl angles.
For the compounds of OX2 where X is a Group 7A element (halogens), the bond angle X–O–X is as follows: OF2, 103.1°; OCl2, 110.9°; OBr2, 112.2°. These varying bond angles can be attributed to the different electronegativities of the halogen attached to O. As the electronegativity decreases, what can you observe on the X–O–X angle?
Alkanes contain only single bonds, alkenes contain double bonds (C=C), and alkynes contain triple bonds (C≡C). Consider the compounds ethane (C2H6), ethene (C2H4), and ethyne (C2H2). Which would have the smallest C–C–H bond angle? Which would have the largest C–C–H bond angle?
Ketones can be derived from the oxidation of secondary alcohols. One example is that acetone (C3H6O) can be prepared from isopropyl alcohol (C3H8O). The Lewis structures of acetone and isopropyl alcohol are shown below:
Based on the given structure, estimate the C–C–O bond angles in each of the compounds.
Draw two structures with the formula C3H7N where there is at most one CH3 group. Identify which structure would have a larger C-N-C bond angle.
Express the bond angles for the given molecules:
CCl4, ICl4-, BF3, and I3
Arrange the variation of the Cl—X—Cl bond angles of NCl3, PCl3, and AsCl3 from ideal values. Explain. (Hint: The electronegativity of the center atom affects the size of the electron pair domain.)