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Multiple Choice
Calculate ΔSsurr (in units of J/K) for the process in which 2.00 mol of water are placed into a freezer at −10.0℃.
A
−22.8 J/K
B
−44.1 J/K
C
−45.8 J/K
D
+22.8 J/K
E
+45.8 J/K
Verified step by step guidance
1
Identify the process: The problem involves calculating the change in entropy of the surroundings (ΔS_surr) when 2.00 mol of water is placed into a freezer at -10.0°C.
Understand the relationship: The change in entropy of the surroundings (ΔS_surr) is related to the heat exchanged with the surroundings (q_surr) and the temperature (T) by the formula: ΔS_surr = -q_sys / T, where q_sys is the heat absorbed or released by the system.
Determine the heat exchange: Since the water is being frozen, it releases heat to the surroundings. The heat released (q_sys) can be calculated using the formula q = n * ΔH_fusion, where n is the number of moles and ΔH_fusion is the enthalpy of fusion for water.
Convert temperature: Ensure the temperature is in Kelvin for the calculation. Convert -10.0°C to Kelvin by adding 273.15, resulting in 263.15 K.
Substitute values into the formula: Use the calculated q_sys and the converted temperature to find ΔS_surr using the formula ΔS_surr = -q_sys / T. This will give you the change in entropy of the surroundings in J/K.