Ethyl propanoate, CH3CH2COOCH2CH3, gives a fruity pineapple-like smell. (a) Draw the Lewis structure for the molecule, assuming that carbon always forms four bonds in its stable compounds. (b) How many s and how many p bonds are in the molecule?
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To draw the Lewis structure of ethyl propanoate, start by identifying the number of valence electrons for each atom: Carbon (C) has 4, Hydrogen (H) has 1, and Oxygen (O) has 6. Calculate the total number of valence electrons in the molecule.
Arrange the atoms in the molecule. Ethyl propanoate has a backbone of carbon atoms with the ester functional group. The structure is CH3CH2COOCH2CH3, where the COO group is the ester linkage.
Connect the atoms with single bonds initially: Connect the carbon atoms in a chain, then attach the oxygen atoms to the appropriate carbon atoms. Ensure each carbon forms four bonds, and each oxygen forms two bonds.
Add lone pairs to the oxygen atoms to satisfy their octet. Adjust the structure to ensure all atoms have a complete octet, using double bonds if necessary, particularly in the COO group.
Count the sigma (σ) and pi (π) bonds: Sigma bonds are single bonds, and each double bond consists of one sigma and one pi bond. Identify the number of each type of bond in the molecule.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Lewis Structures
Lewis structures are diagrams that represent the bonding between atoms in a molecule and the lone pairs of electrons that may exist. They are based on the octet rule, which states that atoms tend to form bonds until they are surrounded by eight valence electrons. In drawing Lewis structures, it is essential to account for the number of valence electrons and ensure that each atom achieves a stable electron configuration.
Chemical bonds can be classified into two main types: sigma (σ) and pi (π) bonds. Sigma bonds are formed by the head-on overlap of atomic orbitals and are the first bonds formed between two atoms. Pi bonds, on the other hand, result from the side-to-side overlap of p orbitals and are typically found in double and triple bonds. Understanding these bond types is crucial for analyzing molecular structure and reactivity.
Hybridization is the concept that describes the mixing of atomic orbitals to form new hybrid orbitals, which can accommodate the bonding requirements of atoms in a molecule. For example, in ethyl propanoate, carbon atoms may undergo sp3 hybridization, resulting in four equivalent hybrid orbitals that can form single bonds with other atoms. This concept helps explain the geometry and bond angles in molecules.