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Multiple Choice
What mass, in grams, of potassium chlorate (KClO3) is needed to contain 0.8542 mol of oxygen atoms?
A
34.5 grams
B
122.5 grams
C
69.0 grams
D
45.8 grams
Verified step by step guidance
1
First, understand the chemical formula of potassium chlorate (KClO3). It contains one potassium (K) atom, one chlorine (Cl) atom, and three oxygen (O) atoms.
Next, determine the number of moles of KClO3 needed to provide 0.8542 moles of oxygen atoms. Since each molecule of KClO3 contains three oxygen atoms, you need to divide the moles of oxygen atoms by 3 to find the moles of KClO3. Use the formula: .
Calculate the molar mass of KClO3. Add the atomic masses of potassium (K), chlorine (Cl), and three oxygen (O) atoms. Use the periodic table to find these values: K = 39.10 g/mol, Cl = 35.45 g/mol, O = 16.00 g/mol. The molar mass of KClO3 is: .
Now, use the moles of KClO3 calculated in step 2 and the molar mass from step 3 to find the mass of KClO3 needed. Use the formula: .
Finally, perform the multiplication to find the mass of KClO3 in grams. This will give you the mass needed to contain 0.8542 mol of oxygen atoms.