Multiple Choice
Which of the following represents the net ionic equation for the reaction between excess hydroiodic acid (HI) and copper(II) carbonate (CuCO3)?
6. Chemical Quantities & Aqueous Reactions
Complete Ionic Equations
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Provide the net ionic equation that occurs when the following aqueous compounds are mixed together:
Copper (II) Bromide and Lithium Hydroxide
A
Cu+ (aq) + OH– (aq) → CuOH (s)
B
Cu2+ (aq) + 2 OH– (aq) → Cu(OH)2 (s)
C
Cu2+ (aq) + 2 H2O (aq) → Cu(OH)2 (s) + 2 H+ (aq)
D
Cu2+ (aq) + OH– (aq) → Cu(OH)2 (s)
Verified step by step guidance1
Identify the reactants: Copper (II) Bromide (CuBr2) and Lithium Hydroxide (LiOH). Both are aqueous, meaning they dissociate into ions in solution.
Write the dissociation equations for each compound: CuBr2 dissociates into Cu2+ and 2 Br-; LiOH dissociates into Li+ and OH-.
Determine the possible products: When Cu2+ and OH- ions combine, they form Copper (II) Hydroxide, Cu(OH)2, which is insoluble in water and precipitates out of the solution.
Write the complete ionic equation by showing all the ions present in the solution before the reaction: Cu2+ (aq) + 2 Br- (aq) + 2 Li+ (aq) + 2 OH- (aq) → Cu(OH)2 (s) + 2 Li+ (aq) + 2 Br- (aq).
Cancel out the spectator ions (ions that appear on both sides of the equation) to write the net ionic equation: Cu2+ (aq) + 2 OH- (aq) → Cu(OH)2 (s).
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