Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

6. Chemical Quantities & Aqueous Reactions

Molecular Equations

General Chemistry

6. Chemical Quantities & Aqueous Reactions

Molecular Equations

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Multiple Choice

What is the balanced molecular equation for the precipitation reaction that occurs when aqueous solutions of lithium bromide and lead(II) acetate are mixed?

2 LiBr(aq) + Pb(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + PbBr2(s)

LiBr(aq) + Pb(C2H3O2)2(aq) → LiPb(aq) + Br2(g)

LiBr(aq) + Pb(C2H3O2)2(aq) → LiC2H3O2(aq) + PbBr2(s)

2 LiBr(aq) + Pb(C2H3O2)2(aq) → 2 LiPb(aq) + 2 Br2(g)

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Verified step by step guidance

Identify the reactants and products in the reaction. The reactants are lithium bromide (LiBr) and lead(II) acetate (Pb(C2H3O2)2). The products will be lithium acetate (LiC2H3O2) and lead(II) bromide (PbBr2).

Write the unbalanced molecular equation using the identified reactants and products: LiBr(aq) + Pb(C2H3O2)2(aq) → LiC2H3O2(aq) + PbBr2(s).

Balance the equation by ensuring the number of atoms of each element is the same on both sides. Start by balancing the lead (Pb) and bromine (Br) atoms. Since there are two bromine atoms in PbBr2, you need two LiBr molecules: 2 LiBr(aq) + Pb(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + PbBr2(s).

Check the balance of lithium (Li) and acetate (C2H3O2) ions. With two LiBr molecules, you have two lithium ions, which matches the two lithium acetate molecules on the product side.

Verify that the equation is balanced by counting the atoms of each element on both sides: 2 Li, 2 Br, 1 Pb, and 2 C2H3O2 on both sides. The balanced molecular equation is: 2 LiBr(aq) + Pb(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + PbBr2(s).